24x^2+56x-10=0

Solution for 24x^2+56x-10=0 equation:

24x^2+56x-10=0

a = 24; b = 56; c = -10;
Δ = b2-4ac
Δ = 562-4·24·(-10)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-64}{2*24}=\frac{-120}{48}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+64}{2*24}=\frac{8}{48}
=1/6
$